-2x^2+13x+34=0

Solution for -2x^2+13x+34=0 equation:

-2x^2+13x+34=0

a = -2; b = 13; c = +34;
Δ = b2-4ac
Δ = 132-4·(-2)·34
Δ = 441
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{441}=21$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(13)-21}{2*-2}=\frac{-34}{-4}
=8+1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(13)+21}{2*-2}=\frac{8}{-4}
=-2
$